What is [(7^{-3})^5]^{-1} ?

The solution to [(7^{-3})^5]^{-1} is 7^{15}

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simplify [(7^{-3})^5]^{-1}

simplify

[(7^{- 3})^{5}]^{- 1}

7^{15}

Decimal Notation

4747561509943

Solution steps

[(7^{- 3})^{5}]^{- 1}

(7^{- 3})^{5} : 7^{- 15}

= [7^{- 15}]^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{7 ^{- 15}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

7^{- 15} = \frac{1}{7 ^{15}}

= \frac{1}{\frac{1}{7 ^{15}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{7 ^{15}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 7^{15}

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e^{4 x} \cdot e^{2 x}

e^{- 1} \cdot 1

e^{- 1} \cdot 4