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Popular >

simplify (h+1)*e^{-bh}

Solution

simplify

(h + 1) \cdot e^{- bh}

Solution

\frac{h + 1}{e ^{bh}}

Solution steps

(h + 1) e^{- bh}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{bh}} (h + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( h + 1 )}{e ^{bh}}

1 \cdot (h + 1) = h + 1

= \frac{h + 1}{e ^{bh}}

Popular Examples

simplify 68e^{-0.0534(4)}simplify

68 e^{- 0.0534 (4)}

simplify (9.16*10^{-3})(5.5*10^6)simplify

(9.16 \cdot 1 0^{- 3}) (5.5 \cdot 1 0^{6})

simplify 9.5*10^{-3}*0.00496049 simplify

9.5 \cdot 1 0^{- 3} \cdot 0.00496049

simplify 17.92*e^{(-1.3*(1000)/(0.2))}simplify

17.92 \cdot e^{(- 1.3 \cdot \frac{1000}{0.2})}

simplify 3583e^{(-e^{(-0.02(200-66))})}simplify

3583 e^{(- e^{(- 0.02 (200 - 66))})}

Frequently Asked Questions (FAQ)

What is (h+1)*e^{-bh} ?
The solution to (h+1)*e^{-bh} is (h+1)/(e^{bh)}