What is (x+1+h)^2(x-1+h)^2 ?

The solution to (x+1+h)^2(x-1+h)^2 is (x+h+1)^2(x+h-1)^2

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simplify (x+1+h)^2(x-1+h)^2

simplify

(x + 1 + h)^{2} (x - 1 + h)^{2}

(x + h + 1)^{2} (x + h - 1)^{2}

Solution steps

(x + 1 + h)^{2} (x - 1 + h)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + h + 1)^{2} (x + h - 1)^{2} = ((x + h + 1) (x + h - 1))^{2}

= ((x + h + 1) (x + h - 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x + h + 1)^{2} (x + h - 1)^{2}

(e^{2 t}) (e^{t})

20 \cdot e^{- 1}

(x 3) \cdot x

7.1 \cdot 1 0^{- 6}

7.1 \cdot 1 0^{- 3}

What is (x+1+h)^2(x-1+h)^2 ?
The solution to (x+1+h)^2(x-1+h)^2 is (x+h+1)^2(x+h-1)^2