What are the solutions to the equation x^2+6x+29=0 ?

The solutions to the equation x^2+6x+29=0 are x=-3+2sqrt(5)i,x=-3-2sqrt(5)i

Find the zeros of x^2+6x+29=0

The zeros of x^2+6x+29=0 are x=-3+2sqrt(5)i,x=-3-2sqrt(5)i

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x^{2} + 6 x + 29 = 0

x = - 3 + 25 i, x = - 3 - 25 i

Solution steps

x^{2} + 6 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 29 : 45 i

x_{1, 2} = \frac{- 6 \pm 4 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4 5 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 4 5 i}{2 \cdot 1}

x = \frac{- 6 + 4 5 i}{2 \cdot 1} : - 3 + 25 i

x = \frac{- 6 - 4 5 i}{2 \cdot 1} : - 3 - 25 i

The solutions to the quadratic equation are:

x = - 3 + 25 i, x = - 3 - 25 i

\frac{- 27}{9} + \frac{- 75}{- 5}

(3 x)^{2} x^{- 7}

\infty - \infty

15 m^{6} n + 28 m^{5} n^{2} + 5 m^{4} n^{3}

What are the solutions to the equation x^2+6x+29=0 ?
The solutions to the equation x^2+6x+29=0 are x=-3+2sqrt(5)i,x=-3-2sqrt(5)i
Find the zeros of x^2+6x+29=0
The zeros of x^2+6x+29=0 are x=-3+2sqrt(5)i,x=-3-2sqrt(5)i