What is cos(2t)e^{-t}e^{-st} ?

The solution to cos(2t)e^{-t}e^{-st} is e^{-t-ts}cos(2t)

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simplify cos(2t)e^{-t}e^{-st}

simplify

cos (2 t) e^{- t} e^{- s t}

e^{- t - t s} cos (2 t)

Solution steps

cos (2 t) e^{- t} e^{- s t}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- t} e^{- s t} = e^{- t - t s}

= cos (2 t) e^{- t - s t}

\frac{0. 5 ^{2}}{2 !} e^{- 0.5}

(cos (x))^{2} \cdot (sin (x))^{2}

(3 w^{3}) 24 w^{3}

4 π \cdot 3.16 \cdot 1 0^{- 6}

- 3 (x - 4)^{2} \cdot (x - 2)^{2}

What is cos(2t)e^{-t}e^{-st} ?
The solution to cos(2t)e^{-t}e^{-st} is e^{-t-ts}cos(2t)