What is t^2*e^{-4t}*u_{-1}(t-5) ?

The solution to t^2*e^{-4t}*u_{-1}(t-5) is (t^2u_{-1}(t-5))/(e^{4t)}

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simplify t^2e^{-4t}u_{-1}(t-5)

simplify

t^{2} \cdot e^{- 4 t} \cdot u_{- 1} (t - 5)

\frac{t ^{2} u _{- 1} ( t - 5 )}{e ^{4 t}}

Solution steps

t^{2} e^{- 4 t} u_{- 1} (t - 5)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{4 t}} t^{2} u_{- 1} (t - 5)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot t ^{2} u _{- 1} ( t - 5 )}{e ^{4 t}}

Multiply:

1 \cdot t^{2} = t^{2}

= \frac{t ^{2} u _{- 1} ( t - 5 )}{e ^{4 t}}

1.9 6^{2} (\frac{1 0 ^{2}}{3 ^{2}})

- 3.6312 \cdot e^{- 0.2136}

\frac{d}{d x} ((x + y^{2})^{4})

What is t^2*e^{-4t}*u_{-1}(t-5) ?
The solution to t^2*e^{-4t}*u_{-1}(t-5) is (t^2u_{-1}(t-5))/(e^{4t)}