What are the solutions to the equation 4x^2+100=0 ?

The solutions to the equation 4x^2+100=0 are x=5i,x=-5i

Find the zeros of 4x^2+100=0

The zeros of 4x^2+100=0 are x=5i,x=-5i

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4 x^{2} + 100 = 0

x = 5 i, x = - 5 i

Solution steps

4 x^{2} + 100 = 0

Move

100

to the right side

4 x^{2} = - 100

Divide both sides by

4

x^{2} = - 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 25, x = - - 25

- 25 = 5 i

- - 25 = - 5 i

x = 5 i, x = - 5 i

\frac{5 \cdot 180}{3}

2 x - \frac{3}{2} = x

∣ 2 x ∣ < 1

\frac{( 2 n + 2 ) !}{( 2 n ) !}

x^{2} - 4 x + 68 = 0

What are the solutions to the equation 4x^2+100=0 ?
The solutions to the equation 4x^2+100=0 are x=5i,x=-5i
Find the zeros of 4x^2+100=0
The zeros of 4x^2+100=0 are x=5i,x=-5i