What is expand e^{-x}(e^{3x}-2e^{2x}+3) ?

The solution to expand e^{-x}(e^{3x}-2e^{2x}+3) is (e^{3x}-2e^{2x}+3)/(e^x)

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expand e^{-x}(e^{3x}-2e^{2x}+3)

expand

e^{- x} (e^{3 x} - 2 e^{2 x} + 3)

\frac{e ^{3 x} - 2 e ^{2 x} + 3}{e ^{x}}

Solution steps

e^{- x} (e^{3 x} - 2 e^{2 x} + 3)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{x}} (e^{3 x} - 2 e^{2 x} + 3)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( e ^{3 x} - 2 e ^{2 x} + 3 )}{e ^{x}}

1 \cdot (e^{3 x} - 2 e^{2 x} + 3) = e^{3 x} - 2 e^{2 x} + 3

= \frac{e ^{3 x} - 2 e ^{2 x} + 3}{e ^{x}}

(12 x^{3} y^{4} z^{5}) x (11 x^{3} y^{4} z^{5})

9 e^{- (2)}

(3.8 \cdot 1 0^{3}) \cdot (9.4 \cdot 1 0^{- 5})

e^{- \frac{t}{a}} u (t)

4.25 \cdot 1 0^{- 5}

What is expand e^{-x}(e^{3x}-2e^{2x}+3) ?
The solution to expand e^{-x}(e^{3x}-2e^{2x}+3) is (e^{3x}-2e^{2x}+3)/(e^x)