What is expand (2x^{4-1/(4x^6)})^8 ?

The solution to expand (2x^{4-1/(4x^6)})^8 is 2^8(x^{-1/(4x^6)+4})^8

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expand (2x^{4-1/(4x^6)})^8

expand

(2 x^{4 - \frac{1}{4 x ^{6}}})^{8}

2^{8} (x^{- \frac{1}{4 x ^{6}} + 4})^{8}

Solution steps

(2 x^{4 - \frac{1}{4 x ^{6}}})^{8}

Apply exponent rule:

(ab)^{c} = a^{c} b^{c}

(2 x^{4 - \frac{1}{4 x ^{6}}})^{8} = 2^{8} (x^{4 - \frac{1}{4 x ^{6}}})^{8}

= 2^{8} (x^{- \frac{1}{4 x ^{6}} + 4})^{8}

7.1 \cdot 1 0^{- 15} \cdot 0.13 3^{7} \cdot 9 0^{\frac{4}{3}}

e^{c o s (x)} \cdot e^{- c o s (x)}

1.81 \cdot 1 0^{- 5}

What is expand (2x^{4-1/(4x^6)})^8 ?
The solution to expand (2x^{4-1/(4x^6)})^8 is 2^8(x^{-1/(4x^6)+4})^8