What is \sqrt[3]{(3x^2+6x-2)^2} ?

The solution to \sqrt[3]{(3x^2+6x-2)^2} is (3x^2+6x-2)^{2/3}

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simplify \sqrt[3]{(3x^2+6x-2)^2}

simplify

(3 x^{2} + 6 x - 2)^{\frac{2}{3}}

Solution steps

Apply radical rule:

= ((3 x^{2} + 6 x - 2)^{2})^{\frac{1}{3}}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (3 x^{2} + 6 x - 2)^{2 \cdot \frac{1}{3}}

2 \cdot \frac{1}{3} = \frac{2}{3}

= (3 x^{2} + 6 x - 2)^{\frac{2}{3}}

2.8 \cdot 8.85 \cdot 1 0^{- 12} \cdot \frac{0.000625}{0.003}

6.72 \cdot 1.9044 \cdot 1 0^{- 6}

e^{- 2 s} \frac{π}{s ^{3} - 6 s ^{2} + 12 s - 8}

680 e^{- 0.0892 t} \cdot (- 0.0892)

What is \sqrt[3]{(3x^2+6x-2)^2} ?
The solution to \sqrt[3]{(3x^2+6x-2)^2} is (3x^2+6x-2)^{2/3}