What is sqrt(pi+1)^{8-(125)^{-1}} ?

The solution to sqrt(pi+1)^{8-(125)^{-1}} is (pi+1)^{999/250}

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simplify sqrt(pi+1)^{8-(125)^{-1}}

simplify

π + 1^{8 - (125)^{- 1}}

(π + 1)^{\frac{999}{250}}

Decimal Notation

292.55050 \dots

Solution steps

(π + 1)^{8 - (125)^{- 1}}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((π + 1)^{\frac{1}{2}})^{8 - 12 5^{- 1}}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (π + 1)^{\frac{1}{2} (8 - 12 5^{- 1})}

\frac{1}{2} (8 - 12 5^{- 1}) = \frac{999}{250}

= (π + 1)^{\frac{999}{250}}

6.9 \cdot 1 0^{- 3}

x \cdot e^{- 1}

(2 x^{3} y) (5 x y^{2}) (3 x y)

x \cdot e^{- 2}

e^{- l n (k)}

What is sqrt(pi+1)^{8-(125)^{-1}} ?
The solution to sqrt(pi+1)^{8-(125)^{-1}} is (pi+1)^{999/250}