What are the solutions to the equation -2x^2-4x+4=0 ?

The solutions to the equation -2x^2-4x+4=0 are x=-1-sqrt(3),x=sqrt(3)-1

Find the zeros of -2x^2-4x+4=0

The zeros of -2x^2-4x+4=0 are x=-1-sqrt(3),x=sqrt(3)-1

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- 2 x^{2} - 4 x + 4 = 0

x = - 1 - 3, x = 3 - 1

Decimal Notation

x = - 2.73205 \dots, x = 0.73205 \dots

Solution steps

- 2 x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 4 = 43

x_{1, 2} = \frac{- ( - 4 ) \pm 4 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 3}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 4 3}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 4 3}{2 ( - 2 )} : - 1 - 3

x = \frac{- ( - 4 ) - 4 3}{2 ( - 2 )} : 3 - 1

The solutions to the quadratic equation are:

x = - 1 - 3, x = 3 - 1

(3 x + 8) (3 x + 8) = 0

\frac{2 k}{3 k + 12} + \frac{k + 7}{k ^{2} + 4 k}

3 r^{3} + 21 r^{2} - 54 r

y^{2} - 3 y + 4 = 0

6 x^{\frac{3}{2}} - 18 x^{\frac{1}{2}} + 12 x^{- \frac{1}{2}}

What are the solutions to the equation -2x^2-4x+4=0 ?
The solutions to the equation -2x^2-4x+4=0 are x=-1-sqrt(3),x=sqrt(3)-1
Find the zeros of -2x^2-4x+4=0
The zeros of -2x^2-4x+4=0 are x=-1-sqrt(3),x=sqrt(3)-1