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Popular >

simplify e^{-ln(t^2+1)}

Solution

simplify

e^{- l n (t^{2} + 1)}

Solution

\frac{1}{t ^{2} + 1}

Solution steps

e^{- l n (t^{2} + 1)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (t^{2} + 1)}}

e^{l n (t^{2} + 1)} = t^{2} + 1

= \frac{1}{t ^{2} + 1}

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Frequently Asked Questions (FAQ)

What is e^{-ln(t^2+1)} ?
The solution to e^{-ln(t^2+1)} is 1/(t^2+1)