What is (1+2t)^{1/2}(1-2t)^{1/2} ?

The solution to (1+2t)^{1/2}(1-2t)^{1/2} is ((2t+1)(-2t+1))^{1/2}

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simplify (1+2t)^{1/2}(1-2t)^{1/2}

simplify

(1 + 2 t)^{\frac{1}{2}} (1 - 2 t)^{\frac{1}{2}}

((2 t + 1) (- 2 t + 1))^{\frac{1}{2}}

Solution steps

(1 + 2 t)^{\frac{1}{2}} (1 - 2 t)^{\frac{1}{2}}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(2 t + 1)^{\frac{1}{2}} (- 2 t + 1)^{\frac{1}{2}} = ((2 t + 1) (- 2 t + 1))^{\frac{1}{2}}

= ((2 t + 1) (- 2 t + 1))^{\frac{1}{2}}

2.25 \cdot 1 0^{- 1}

(500 (2 \cdot π \cdot 0.04 \cdot 8.854 \cdot 1 0^{- 12})) \cdot 0.009

e^{- l n (x - y)}

(4.2 x 1 0^{6}) (2 x 1 0^{- 4})

1.588 \cdot 1 0^{- 1}

What is (1+2t)^{1/2}(1-2t)^{1/2} ?
The solution to (1+2t)^{1/2}(1-2t)^{1/2} is ((2t+1)(-2t+1))^{1/2}