What is (2x^4)(2x^2)(4x^5) ?

The solution to (2x^4)(2x^2)(4x^5) is 16x^{11}

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simplify (2x^4)(2x^2)(4x^5)

simplify

(2 x^{4}) (2 x^{2}) (4 x^{5})

16 x^{11}

Solution steps

(2 x^{4}) (2 x^{2}) (4 x^{5})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2 \cdot 2 = 2^{1 + 1}

= x^{4} \cdot 2^{1 + 1} x^{2} \cdot 4 x^{5}

Add the numbers:

1 + 1 = 2

= x^{4} \cdot 2^{2} x^{2} \cdot 4 x^{5}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{4} x^{2} x^{5} = x^{4 + 2 + 5}

= 2^{2} \cdot 4 x^{4 + 2 + 5}

Add the numbers:

4 + 2 + 5 = 11

= 2^{2} \cdot 4 x^{11}

2^{2} = 4

= 4 \cdot 4 x^{11}

Multiply the numbers:

4 \cdot 4 = 16

= 16 x^{11}

e e^{e - 1}

4.59 x 1 0^{- 3}

- 2 1 - x (2 1 - x)

- 1.38 \cdot 1 0^{- 23} \cdot 298 \cdot ln (1 0^{- 2.19})

(0.5 \cdot 1 0^{- 6}) (- 4 e^{- (t - 1)})