What is the d/(dt)((x)(y(x,t)^{-3})) ?

The d/(dt)((x)(y(x,t)^{-3})) is xy(-3/((x,t)^4)(x,1))

What is the first d/(dt)((x)(y(x,t)^{-3})) ?

The first d/(dt)((x)(y(x,t)^{-3})) is xy(-3/((x,t)^4)(x,1))

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\frac{d}{d t} ((x) (y (x, t)^{- 3}))

x y (- \frac{3}{( x , t ) ^{4}} (x, 1))

Solution steps

\frac{d}{d t} ((x) (y (x, t)^{- 3}))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x y \frac{d}{d t} ((x, t)^{- 3})

Apply the chain rule:

- \frac{3}{( x , t ) ^{4}} \frac{d}{d t} (x, t)

= - \frac{3}{( x , t ) ^{4}} \frac{d}{d t} (x, t)

\frac{d}{d t} (x, t) = (x, 1)

= x y (- \frac{3}{( x , t ) ^{4}} (x, 1))

f (x) = - \frac{x}{2}

e^{- (p^{2})^{\frac{3}{2}}}

- \frac{1}{2} e^{- 1}

6.674 \cdot 1 0^{- 11} (\frac{5 \cdot 10}{2 ^{2}})

1 6^{\frac{5}{6}} \cdot 4^{\frac{5}{6}}

What is the d/(dt)((x)(y(x,t)^{-3})) ?
The d/(dt)((x)(y(x,t)^{-3})) is xy(-3/((x,t)^4)(x,1))
What is the first d/(dt)((x)(y(x,t)^{-3})) ?
The first d/(dt)((x)(y(x,t)^{-3})) is xy(-3/((x,t)^4)(x,1))