What are the solutions to the equation 4x^2+77=36x ?

The solutions to the equation 4x^2+77=36x are x= 11/2 ,x= 7/2

Find the zeros of 4x^2+77=36x

The zeros of 4x^2+77=36x are x= 11/2 ,x= 7/2

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4 x^{2} + 77 = 36 x

x = \frac{11}{2}, x = \frac{7}{2}

Decimal Notation

x = 5.5, x = 3.5

Solution steps

4 x^{2} + 77 = 36 x

Move

36 x

to the left side

4 x^{2} + 77 - 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 36 x + 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 77}{2 \cdot 4}

(- 36)^{2} - 4 \cdot 4 \cdot 77 = 8

x_{1, 2} = \frac{- ( - 36 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 8}{2 \cdot 4}

x = \frac{- ( - 36 ) + 8}{2 \cdot 4} : \frac{11}{2}

x = \frac{- ( - 36 ) - 8}{2 \cdot 4} : \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{11}{2}, x = \frac{7}{2}

ln (ln (e^{e^{6}}))

16 x^{2} - 36 = 0

p^{2} = 0.81

2 (2 + x) - (6 - 7 x) = 13 x - (1 + 4 x)

24 p^{2} - 28

What are the solutions to the equation 4x^2+77=36x ?
The solutions to the equation 4x^2+77=36x are x= 11/2 ,x= 7/2
Find the zeros of 4x^2+77=36x
The zeros of 4x^2+77=36x are x= 11/2 ,x= 7/2