What is 10^{-12}*(-log_{10}(7.418)) ?

The solution to 10^{-12}*(-log_{10}(7.418)) is (-log_{10}(7418)+3)/(10^{12)}

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simplify 10^{-12}*(-log_{10}(7.418))

simplify

1 0^{- 12} \cdot (- lo g_{10} (7.418))

\frac{- lo g _{10} ( 7418 ) + 3}{1 0 ^{12}}

Decimal Notation

- 8.70287 E - 13

Solution steps

1 0^{- 12} (- lo g_{10} (7.418))

Apply rule:

a (- b) = - ab

1 0^{- 12} (- lo g_{10} (7.418)) = - 1 0^{- 12} lo g_{10} (7.418)

= - 1 0^{- 12} lo g_{10} (7.418)

lo g_{10} (7.418) = lo g_{10} (7418) - 3

= - 1 0^{- 12} (lo g_{10} (7418) - 3)

Simplify

- 1 0^{- 12} (lo g_{10} (7418) - 3) : - \frac{1}{1 0 ^{12}} lo g_{10} (7418) + \frac{3}{1 0 ^{12}}

= - \frac{1}{1 0 ^{12}} lo g_{10} (7418) + \frac{3}{1 0 ^{12}}

- \frac{1}{1 0 ^{12}} lo g_{10} (7418) + \frac{3}{1 0 ^{12}} = \frac{- lo g _{10} ( 7418 ) + 3}{1 0 ^{12}}

= \frac{- lo g _{10} ( 7418 ) + 3}{1 0 ^{12}}

x^{2} (2 x + 1)^{2}

0.984 e^{- 0.0123 (2)}

2 (9.11 \cdot 1 0^{- 31})

e^{- \frac{3}{2} π}

What is 10^{-12}*(-log_{10}(7.418)) ?
The solution to 10^{-12}*(-log_{10}(7.418)) is (-log_{10}(7418)+3)/(10^{12)}