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Popular >

simplify e^{-ln|y^2-1|}

Solution

simplify

e^{- l n ∣ y^{2} - 1 ∣}

Solution

\frac{1}{∣ y ^{2} - 1 ∣}

Solution steps

e^{- l n ∣ y^{2} - 1 ∣}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n ∣ y^{2} - 1 ∣}}

e^{l n ∣ y^{2} - 1 ∣} = y^{2} - 1

= \frac{1}{∣ y ^{2} - 1 ∣}

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Frequently Asked Questions (FAQ)

What is e^{-ln|y^2-1|} ?
The solution to e^{-ln|y^2-1|} is 1/(|y^2-1|)