What are the solutions to the equation 19m^2+5m-12=-6m^2 ?

The solutions to the equation 19m^2+5m-12=-6m^2 are m= 3/5 ,m=-4/5

Find the zeros of 19m^2+5m-12=-6m^2

The zeros of 19m^2+5m-12=-6m^2 are m= 3/5 ,m=-4/5

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19 m^{2} + 5 m - 12 = - 6 m^{2}

m = \frac{3}{5}, m = - \frac{4}{5}

Decimal Notation

m = 0.6, m = - 0.8

Solution steps

19 m^{2} + 5 m - 12 = - 6 m^{2}

Move

6 m^{2}

to the left side

25 m^{2} + 5 m - 12 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 25 ( - 12 )}{2 \cdot 25}

5^{2} - 4 \cdot 25 (- 12) = 35

m_{1, 2} = \frac{- 5 \pm 35}{2 \cdot 25}

Separate the solutions

m_{1} = \frac{- 5 + 35}{2 \cdot 25}, m_{2} = \frac{- 5 - 35}{2 \cdot 25}

m = \frac{- 5 + 35}{2 \cdot 25} : \frac{3}{5}

m = \frac{- 5 - 35}{2 \cdot 25} : - \frac{4}{5}

The solutions to the quadratic equation are:

m = \frac{3}{5}, m = - \frac{4}{5}

∣ 7 y - 5 ∣ \geq - 31

∣ 6 (r - 3) ∣ = 1.8

\frac{x ^{3} + y ^{3}}{x ^{2} + y ^{2}}

z^{2} + 9 y^{2} z

\frac{1}{2} x = 8

What are the solutions to the equation 19m^2+5m-12=-6m^2 ?
The solutions to the equation 19m^2+5m-12=-6m^2 are m= 3/5 ,m=-4/5
Find the zeros of 19m^2+5m-12=-6m^2
The zeros of 19m^2+5m-12=-6m^2 are m= 3/5 ,m=-4/5