What is 1/2 (e/(e^{x+2)})^{-5} ?

The solution to 1/2 (e/(e^{x+2)})^{-5} is 1/(2e^{5(-x-1))}

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simplify 1/2 (e/(e^{x+2)})^{-5}

simplify

\frac{1}{2} (\frac{e}{e ^{x + 2}})^{- 5}

\frac{1}{2 e ^{5 (- x - 1)}}

Solution steps

\frac{1}{2} (\frac{e}{e ^{x + 2}})^{- 5}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{2} \cdot \frac{1}{( \frac{e}{e ^{x + 2}} ) ^{5}}

\frac{1}{( \frac{e}{e ^{x + 2}} ) ^{5}} = \frac{1}{e ^{5 (- x - 1)}}

= \frac{1}{2} \cdot \frac{1}{e ^{5 (- x - 1)}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{2 e ^{(- x - 1) \cdot 5}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{2 e ^{5 (- x - 1)}}

- \frac{3}{3}

993.66 e^{- 53.1 (0.1)}

(7.42 \cdot 1 0^{- 6}) (2 π) (0.0159)

(7.7 \cdot 1 0^{8}) \cdot (4.9 \cdot 1 0^{- 5})

What is 1/2 (e/(e^{x+2)})^{-5} ?
The solution to 1/2 (e/(e^{x+2)})^{-5} is 1/(2e^{5(-x-1))}