What is (x^2-1)^{1/2}(x^2+1)^{1/2} ?

The solution to (x^2-1)^{1/2}(x^2+1)^{1/2} is ((x^2-1)(x^2+1))^{1/2}

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simplify (x^2-1)^{1/2}(x^2+1)^{1/2}

simplify

(x^{2} - 1)^{\frac{1}{2}} (x^{2} + 1)^{\frac{1}{2}}

((x^{2} - 1) (x^{2} + 1))^{\frac{1}{2}}

Solution steps

(x^{2} - 1)^{\frac{1}{2}} (x^{2} + 1)^{\frac{1}{2}}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} - 1)^{\frac{1}{2}} (x^{2} + 1)^{\frac{1}{2}} = ((x^{2} - 1) (x^{2} + 1))^{\frac{1}{2}}

= ((x^{2} - 1) (x^{2} + 1))^{\frac{1}{2}}

4 π 0. 1^{- 7}

e^{5 t} (e^{3 t})

\frac{51}{65}

e^{- 60 (3)}

What is (x^2-1)^{1/2}(x^2+1)^{1/2} ?
The solution to (x^2-1)^{1/2}(x^2+1)^{1/2} is ((x^2-1)(x^2+1))^{1/2}