What are the solutions to the equation 3x^2-4x-2=0 ?

The solutions to the equation 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3

Find the zeros of 3x^2-4x-2=0

The zeros of 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3

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3 x^{2} - 4 x - 2 = 0

x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

Decimal Notation

x = 1.72075 \dots, x = - 0.38742 \dots

Solution steps

3 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 2) = 210

x_{1, 2} = \frac{- ( - 4 ) \pm 2 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 10}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 10}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 10}{2 \cdot 3} : \frac{2 + 10}{3}

x = \frac{- ( - 4 ) - 2 10}{2 \cdot 3} : \frac{2 - 10}{3}

The solutions to the quadratic equation are:

x = \frac{2 + 10}{3}, x = \frac{2 - 10}{3}

2 (x - 4) + 3 x - x^{2} = 3

- 8 \leq 1 - 3 (x - 2) < 13

(1 - 0.537) = \frac{x}{\frac{500}{0.55} + 100.02}

\frac{m ^{- 6} n ^{- 3}}{m ^{- 13} n ^{- 1}}

\frac{x ^{2}}{4} = \frac{x + 4}{2}

What are the solutions to the equation 3x^2-4x-2=0 ?
The solutions to the equation 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3
Find the zeros of 3x^2-4x-2=0
The zeros of 3x^2-4x-2=0 are x=(2+sqrt(10))/3 ,x=(2-sqrt(10))/3