What is m^2*(x(1-e^{(-y)/(zm)}))^2*(1/(y^2)) ?

The solution to m^2*(x(1-e^{(-y)/(zm)}))^2*(1/(y^2)) is (m^2x^2(-e^{-y/(mz)}+1)^2)/(y^2)

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simplify m^2(x(1-e^{(-y)/(zm)}))^2(1/(y^2))

simplify

m^{2} \cdot (x (1 - e^{\frac{- y}{z m}}))^{2} \cdot (\frac{1}{y ^{2}})

\frac{m ^{2} x ^{2} ( - e ^{- \frac{y}{m z}} + 1 ) ^{2}}{y ^{2}}

Solution steps

m^{2} (x (1 - e^{\frac{- y}{z m}}))^{2} (\frac{1}{y ^{2}})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

m^{2} (x (- e^{\frac{- y}{m z}} + 1))^{2} = (m x (- e^{\frac{- y}{m z}} + 1))^{2}

= \frac{1}{y ^{2}} (m x (- e^{\frac{- y}{m z}} + 1))^{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= \frac{1}{y ^{2}} (m x (- e^{- \frac{y}{m z}} + 1))^{2}

(m x (1 - e^{- \frac{y}{m z}}))^{2} = m^{2} x^{2} (1 - e^{- \frac{y}{m z}})^{2}

= \frac{1}{y ^{2}} m^{2} x^{2} (- e^{- \frac{y}{m z}} + 1)^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot m ^{2} x ^{2} ( 1 - e ^{- \frac{y}{m z}} ) ^{2}}{y ^{2}}

Multiply:

1 \cdot m^{2} = m^{2}

= \frac{m ^{2} x ^{2} ( - e ^{- \frac{y}{m z}} + 1 ) ^{2}}{y ^{2}}

4 e^{- 22}

(8 z^{7}) (5 z^{4}) (6 z^{5})

- 10000 e^{- 0.01 (1.7 \cdot 60)}

e^{- 11.7}

What is m^2*(x(1-e^{(-y)/(zm)}))^2*(1/(y^2)) ?
The solution to m^2*(x(1-e^{(-y)/(zm)}))^2*(1/(y^2)) is (m^2x^2(-e^{-y/(mz)}+1)^2)/(y^2)