What are the solutions to the equation x(x+2)=3 ?

The solutions to the equation x(x+2)=3 are x=1,x=-3

Find the zeros of x(x+2)=3

The zeros of x(x+2)=3 are x=1,x=-3

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x (x + 2) = 3

x = 1, x = - 3

Solution steps

x (x + 2) = 3

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 3

Move

3

to the left side

x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 \cdot 1}, x_{2} = \frac{- 2 - 4}{2 \cdot 1}

x = \frac{- 2 + 4}{2 \cdot 1} : 1

x = \frac{- 2 - 4}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

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7 x^{2} - 3 x = 2

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What are the solutions to the equation x(x+2)=3 ?
The solutions to the equation x(x+2)=3 are x=1,x=-3
Find the zeros of x(x+2)=3
The zeros of x(x+2)=3 are x=1,x=-3