What is (1+C/(e^{zk)})^{-1} ?

The solution to (1+C/(e^{zk)})^{-1} is (e^{kz})/(C+e^{kz)}

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simplify (1+C/(e^{zk)})^{-1}

simplify

(1 + \frac{C}{e ^{z k}})^{- 1}

\frac{e ^{k z}}{C + e ^{k z}}

Solution steps

(1 + \frac{C}{e ^{z k}})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{( 1 + \frac{C}{e ^{k z}} )}

Join

1 + \frac{C}{e ^{z k}} : \frac{e ^{k z} + C}{e ^{k z}}

= \frac{1}{\frac{e ^{k z} + C}{e ^{k z}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{e ^{z k}}{e ^{z k} + C}

t^{- 1} (e^{2 t} - e^{2 t} cos (3 t))

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100000 \cdot 1.2 \cdot 0. 6^{- 1}

π^{5} \cdot π^{6} \cdot π^{9} \cdot π^{12}

What is (1+C/(e^{zk)})^{-1} ?
The solution to (1+C/(e^{zk)})^{-1} is (e^{kz})/(C+e^{kz)}