What is (7abc)(2a^3bc) ?

The solution to (7abc)(2a^3bc) is 14a^4b^2c^2

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simplify (7abc)(2a^3bc)

simplify

(7 ab c) (2 a^{3} b c)

14 a^{4} b^{2} c^{2}

Solution steps

(7 ab c) (2 a^{3} b c)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a a^{3} = a^{1 + 3}

= 7 b c \cdot 2 a^{1 + 3} b c

Add the numbers:

1 + 3 = 4

= 7 b c \cdot 2 a^{4} b c

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

bb = b^{1 + 1}

= 7 c \cdot 2 a^{4} b^{1 + 1} c

Add the numbers:

1 + 1 = 2

= 7 c \cdot 2 a^{4} b^{2} c

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

cc = c^{1 + 1}

= 7 \cdot 2 a^{4} b^{2} c^{1 + 1}

Add the numbers:

1 + 1 = 2

= 7 \cdot 2 a^{4} b^{2} c^{2}

Multiply the numbers:

7 \cdot 2 = 14

= 14 a^{4} b^{2} c^{2}

y^{\frac{1}{2}} (2 y^{\frac{1}{2}})

0.5 \cdot 400000 \cdot 0. 5^{2}

0.83425 \cdot (0.1)^{- 0.21649}

e^{- \frac{6}{10}}

2 k^{\circ} 4 k