What is 9e^{-0.7x}cos(4x) ?

The solution to 9e^{-0.7x}cos(4x) is (9cos(4x))/(e^{0.7x)}

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simplify 9e^{-0.7x}cos(4x)

simplify

9 e^{- 0.7 x} cos (4 x)

\frac{9 cos ( 4 x )}{e ^{0.7 x}}

Solution steps

9 e^{- 0.7 x} cos (4 x)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 9 \cdot \frac{1}{e ^{0.7 x}} cos (4 x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 9 cos ( 4 x )}{e ^{0.7 x}}

Multiply the numbers:

1 \cdot 9 = 9

= \frac{9 cos ( 4 x )}{e ^{0.7 x}}

- \frac{1}{2} x (2 x^{2})

2 5^{2} \cdot 12 5^{2}

31.25 e^{- \frac{0}{0.32}}

What is 9e^{-0.7x}cos(4x) ?
The solution to 9e^{-0.7x}cos(4x) is (9cos(4x))/(e^{0.7x)}