What are the solutions to the equation 0=3x^2+6x+1 ?

The solutions to the equation 0=3x^2+6x+1 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3

Find the zeros of 0=3x^2+6x+1

The zeros of 0=3x^2+6x+1 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3

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0 = 3 x^{2} + 6 x + 1

x = \frac{- 3 + 6}{3}, x = - \frac{3 + 6}{3}

Decimal Notation

x = - 0.18350 \dots, x = - 1.81649 \dots

Solution steps

0 = 3 x^{2} + 6 x + 1

Switch sides

3 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 1 = 26

x_{1, 2} = \frac{- 6 \pm 2 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 6}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 6}{2 \cdot 3}

x = \frac{- 6 + 2 6}{2 \cdot 3} : \frac{- 3 + 6}{3}

x = \frac{- 6 - 2 6}{2 \cdot 3} : - \frac{3 + 6}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 6}{3}, x = - \frac{3 + 6}{3}

∣ 3 - x ∣ < 4

∣ 7 x + 1 ∣ < 9

(x + y)^{3} - (2 + 3 y)^{3}

2 x^{2} - \frac{10}{3} x + \frac{4}{3} = 0

3 x^{2} - 11 x + 10

What are the solutions to the equation 0=3x^2+6x+1 ?
The solutions to the equation 0=3x^2+6x+1 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3
Find the zeros of 0=3x^2+6x+1
The zeros of 0=3x^2+6x+1 are x=(-3+sqrt(6))/3 ,x=-(3+sqrt(6))/3