What is 1/2 (x^2+ln(5x-3y^2))^{-1/2} ?

The solution to 1/2 (x^2+ln(5x-3y^2))^{-1/2} is 1/(2(x^2+ln(5x-3y^2))^{1/2)}

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simplify 1/2 (x^2+ln(5x-3y^2))^{-1/2}

simplify

\frac{1}{2} (x^{2} + ln (5 x - 3 y^{2}))^{- \frac{1}{2}}

\frac{1}{2 ( x ^{2} + ln ( 5 x - 3 y ^{2} ) ) ^{\frac{1}{2}}}

Solution steps

\frac{1}{2} (x^{2} + ln (5 x - 3 y^{2}))^{- \frac{1}{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{2} \cdot \frac{1}{( x ^{2} + ln ( 5 x - 3 y ^{2} ) ) ^{\frac{1}{2}}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{2 ( x ^{2} + ln ( 5 x - 3 y ^{2} ) ) ^{\frac{1}{2}}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{2 ( x ^{2} + ln ( 5 x - 3 y ^{2} ) ) ^{\frac{1}{2}}}

2 e^{- \frac{x}{2}} (- \frac{1}{2})

(5 x^{\frac{2}{3}}) (4 x^{\frac{1}{4}})

(4.29 \cdot 1 0^{15}) \cdot (1.99 \cdot 1 0^{- 4})

(22) \cdot 2

What is 1/2 (x^2+ln(5x-3y^2))^{-1/2} ?
The solution to 1/2 (x^2+ln(5x-3y^2))^{-1/2} is 1/(2(x^2+ln(5x-3y^2))^{1/2)}