What is algebra(1-3x+2x^2)/((x^2+1)(x^2-1)) ?

The solution to algebra(1-3x+2x^2)/((x^2+1)(x^2-1)) is (ea^2lbgr(2x-1))/((x+1)(x^2+1))

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simplify algebra(1-3x+2x^2)/((x^2+1)(x^2-1))

simplify

a l g e b r a \frac{1 - 3 x + 2 x ^{2}}{( x ^{2} + 1 ) ( x ^{2} - 1 )}

\frac{e a ^{2} l b g r ( 2 x - 1 )}{( x + 1 ) ( x ^{2} + 1 )}

Solution steps

a l g e b r a \frac{1 - 3 x + 2 x ^{2}}{( x ^{2} + 1 ) ( x ^{2} - 1 )}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

aa = a^{1 + 1}

= l g e b r a^{1 + 1} \frac{1 - 3 x + 2 x ^{2}}{( x ^{2} + 1 ) ( x ^{2} - 1 )}

Add the numbers:

1 + 1 = 2

= l g e b r a^{2} \frac{1 - 3 x + 2 x ^{2}}{( x ^{2} + 1 ) ( x ^{2} - 1 )}

\frac{1 - 3 x + 2 x ^{2}}{( x ^{2} + 1 ) ( x ^{2} - 1 )} = \frac{2 x - 1}{( x + 1 ) ( x ^{2} + 1 )}

= e a^{2} l b g r \frac{2 x - 1}{( x + 1 ) ( x ^{2} + 1 )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x - 1 ) l g e b r a ^{2}}{( x + 1 ) ( x ^{2} + 1 )}

4 π sin (2 π rs t^{3}) 4 s^{2} t (t^{3}) cos (2 π s t^{3})

- (x e^{- x^{2}})

2 (5.67 \cdot 1 0^{- 8}) (266.32)^{4}

x^{3} (2 x^{2})

What is algebra(1-3x+2x^2)/((x^2+1)(x^2-1)) ?
The solution to algebra(1-3x+2x^2)/((x^2+1)(x^2-1)) is (ea^2lbgr(2x-1))/((x+1)(x^2+1))