What are the solutions to the equation 2w^2+9w+9=0 ?

The solutions to the equation 2w^2+9w+9=0 are w=-3/2 ,w=-3

Find the zeros of 2w^2+9w+9=0

The zeros of 2w^2+9w+9=0 are w=-3/2 ,w=-3

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2 w^{2} + 9 w + 9 = 0

w = - \frac{3}{2}, w = - 3

Decimal Notation

w = - 1.5, w = - 3

Solution steps

2 w^{2} + 9 w + 9 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 9}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 9 = 3

w_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 9 + 3}{2 \cdot 2}, w_{2} = \frac{- 9 - 3}{2 \cdot 2}

w = \frac{- 9 + 3}{2 \cdot 2} : - \frac{3}{2}

w = \frac{- 9 - 3}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

w = - \frac{3}{2}, w = - 3

(x + 3 i) (x - 3 i)

x^{2} + \frac{40 x}{12} + \frac{128}{60} = 0

(- 4 + i) (- 4 - i)

(- \frac{1}{5})^{- 1}

\frac{10}{x + 2} > 0

What are the solutions to the equation 2w^2+9w+9=0 ?
The solutions to the equation 2w^2+9w+9=0 are w=-3/2 ,w=-3
Find the zeros of 2w^2+9w+9=0
The zeros of 2w^2+9w+9=0 are w=-3/2 ,w=-3