What is (3/4 p^4q^5r)(8/9 p^2q^3r^6) ?

The solution to (3/4 p^4q^5r)(8/9 p^2q^3r^6) is (2p^6q^8r^7)/3

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simplify (3/4 p^4q^5r)(8/9 p^2q^3r^6)

simplify

(\frac{3}{4} p^{4} q^{5} r) (\frac{8}{9} p^{2} q^{3} r^{6})

\frac{2 p ^{6} q ^{8} r ^{7}}{3}

Solution steps

(\frac{3}{4} p^{4} q^{5} r) (\frac{8}{9} p^{2} q^{3} r^{6})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

p^{4} p^{2} = p^{4 + 2}

= \frac{3}{4} q^{5} r \frac{8}{9} p^{4 + 2} q^{3} r^{6}

Add the numbers:

4 + 2 = 6

= \frac{3}{4} q^{5} r \frac{8}{9} p^{6} q^{3} r^{6}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

q^{5} q^{3} = q^{5 + 3}

= \frac{3}{4} r \frac{8}{9} p^{6} q^{5 + 3} r^{6}

Add the numbers:

5 + 3 = 8

= \frac{3}{4} r \frac{8}{9} p^{6} q^{8} r^{6}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

r r^{6} = r^{1 + 6}

= \frac{3}{4} \cdot \frac{8}{9} p^{6} q^{8} r^{1 + 6}

Add the numbers:

1 + 6 = 7

= \frac{3}{4} \cdot \frac{8}{9} p^{6} q^{8} r^{7}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{3 \cdot 8 p ^{6} q ^{8} r ^{7}}{4 \cdot 9}

Refine

= \frac{24 p ^{6} q ^{8} r ^{7}}{36}

Cancel the common factor:

12

= \frac{2 p ^{6} q ^{8} r ^{7}}{3}

e^{- \frac{1}{0.75}} \cdot (1 - e^{- \frac{1}{0.75}})^{4}

1000 \cdot 501.72 \cdot 1 0^{- 6}

(\frac{50}{1.388 \cdot 1 0 ^{- 2}}) \cdot 1 0^{- 6}

(3 x^{2} y^{4}) (4 x y^{2})

5.7 \cdot 1 0^{- 6}

What is (3/4 p^4q^5r)(8/9 p^2q^3r^6) ?
The solution to (3/4 p^4q^5r)(8/9 p^2q^3r^6) is (2p^6q^8r^7)/3