What is expand \sqrt[n]{((2n-9)^{2n})/((-3n-7)^{2n)}} ?

The solution to expand \sqrt[n]{((2n-9)^{2n})/((-3n-7)^{2n)}} is ((2n-9)^2)/((-3n-7)^2)

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expand \sqrt[n]{((2n-9)^{2n})/((-3n-7)^{2n)}}

expand

\frac{( 2 n - 9 ) ^{2}}{( - 3 n - 7 ) ^{2}}

Solution steps

Apply radical rule:

Simplify

= \frac{( 2 n - 9 ) ^{2}}{( - 3 n - 7 ) ^{2}}

100 \cdot e^{- 403.932}

101.32 5^{- \frac{9.81}{( 287 ) ( 276 )} \cdot 3624}

4 \cdot π \cdot 69634000 0^{2} \cdot 5678 \cdot 1 0^{- 8}

\frac{2}{3} 2^{\frac{3}{2}}

What is expand \sqrt[n]{((2n-9)^{2n})/((-3n-7)^{2n)}} ?
The solution to expand \sqrt[n]{((2n-9)^{2n})/((-3n-7)^{2n)}} is ((2n-9)^2)/((-3n-7)^2)