What is (1/s-1/(s+1))e^{-2s} ?

The solution to (1/s-1/(s+1))e^{-2s} is 1/(e^{2s)s(s+1)}

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simplify (1/s-1/(s+1))e^{-2s}

simplify

(\frac{1}{s} - \frac{1}{s + 1}) e^{- 2 s}

\frac{1}{e ^{2 s} s ( s + 1 )}

Solution steps

(\frac{1}{s} - \frac{1}{s + 1}) e^{- 2 s}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 s}} (\frac{1}{s} - \frac{1}{s + 1})

Join

\frac{1}{s} - \frac{1}{s + 1} : \frac{1}{s ( s + 1 )}

= \frac{1}{s ( s + 1 )} \cdot \frac{1}{e ^{2 s}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 1}{s ( s + 1 ) e ^{2 s}}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{e ^{2 s} s ( s + 1 )}

e^{3} \cdot e^{- 5}

(0.1 M) (0.2 MN) (10 M^{2} N^{2})

\frac{5}{2} x^{- 0.5}

(5 m^{4}) (6 m^{3})

6.0309 \cdot 1 0^{- 4}

What is (1/s-1/(s+1))e^{-2s} ?
The solution to (1/s-1/(s+1))e^{-2s} is 1/(e^{2s)s(s+1)}