What is 3x^2y^2(-3x^3+2x^2y+4y^5) ?

The solution to 3x^2y^2(-3x^3+2x^2y+4y^5) is 3x^2y^2(-3x^3+2x^2y+4y^5)

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simplify 3x^2y^2(-3x^3+2x^2y+4y^5)

simplify

3 x^{2} y^{2} (- 3 x^{3} + 2 x^{2} y + 4 y^{5})

3 x^{2} y^{2} (- 3 x^{3} + 2 x^{2} y + 4 y^{5})

Solution steps

3 x^{2} y^{2} (- 3 x^{3} + 2 x^{2} y + 4 y^{5})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} y^{2} = (x y)^{2}

= 3 (x y)^{2} (- 3 x^{3} + 2 x^{2} y + 4 y^{5})

(x y)^{2} = x^{2} y^{2}

= 3 x^{2} y^{2} (- 3 x^{3} + 2 x^{2} y + 4 y^{5})

h (x^{2} (x + h)^{2})

e^{- 1.6} \cdot (\frac{1. 6 ^{4}}{4 !})

2^{7} \cdot 3^{7}

x^{- 2 = 36}

\frac{1}{4} e^{- l n (x) y}

What is 3x^2y^2(-3x^3+2x^2y+4y^5) ?
The solution to 3x^2y^2(-3x^3+2x^2y+4y^5) is 3x^2y^2(-3x^3+2x^2y+4y^5)