What is 2*1*10^{-7}((2*0.65)/(0.25)) ?

The solution to 2*1*10^{-7}((2*0.65)/(0.25)) is 13/12500000

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simplify 2110^{-7}((2*0.65)/(0.25))

simplify

2 \cdot 1 \cdot 1 0^{- 7} (\frac{2 \cdot 0.65}{0.25})

\frac{13}{12500000}

Decimal Notation

0.00000104

Solution steps

2 \cdot 1 \cdot 1 0^{- 7} (\frac{2 \cdot 0.65}{0.25})

Apply rule:

a \cdot 1 = a

= 2 \cdot 1 0^{- 7} \cdot \frac{2 \cdot 0.65}{0.25}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 7} = \frac{1}{1 0 ^{7}}

= 2 \cdot \frac{1}{1 0 ^{7}} \cdot \frac{2 \cdot 0.65}{0.25}

1 0^{7} = 10000000

= 2 \cdot \frac{1}{10000000} \cdot \frac{2 \cdot 0.65}{0.25}

2 \cdot \frac{1}{10000000} \cdot \frac{2 \cdot 0.65}{0.25} = \frac{2.6}{2500000}

= \frac{2.6}{2500000}

\frac{2.6}{2500000} = \frac{26}{25000000}

= \frac{26}{25000000}

Factor the number:

26 = 2 \cdot 13

= \frac{2 \cdot 13}{25000000}

Factor the number:

25000000 = 2 \cdot 12500000

= \frac{2 \cdot 13}{2 \cdot 12500000}

Cancel the common factor:

2

= \frac{13}{12500000}

15000 e^{- 6286 (5)}

d^{- 1} x cos (x) d x

e^{- b t}

(\frac{4 - 7}{3} - 1)^{3}

What is 2*1*10^{-7}((2*0.65)/(0.25)) ?
The solution to 2*1*10^{-7}((2*0.65)/(0.25)) is 13/12500000