What is (4^{1/3})^{(x^2-1)=\sqrt[3]{16}} ?

The solution to (4^{1/3})^{(x^2-1)=\sqrt[3]{16}} is 4^{1/3 (x^2-1*\sqrt[3]{16}=)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4^{1/3})^{(x^2-1)=\sqrt[3]{16}}

simplify

Solution steps

Apply exponent rule:

(a^{b})^{c} = a^{b c}

1 0^{- l o g_{10} (7.63 \cdot 1 0^{- 4})}

(f \circ g) x x^{2} + 1

300 (e^{0.5})^{3}

s^{2} (s - 1)^{2}

What is (4^{1/3})^{(x^2-1)=\sqrt[3]{16}} ?
The solution to (4^{1/3})^{(x^2-1)=\sqrt[3]{16}} is 4^{1/3 (x^2-1*\sqrt[3]{16}=)}