What is (3a\sqrt[3]{2b^2})(2a^2\sqrt[3]{4b^2}) ?

The solution to (3a\sqrt[3]{2b^2})(2a^2\sqrt[3]{4b^2}) is 6\sqrt[3]{2}*2^{2/3}a^3b^{4/3}

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simplify (3a\sqrt[3]{2b^2})(2a^2\sqrt[3]{4b^2})

simplify

Solution steps

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a a^{2} = a^{1 + 2}

Add the numbers:

1 + 2 = 3

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b^{\frac{2}{3}} b^{\frac{2}{3}} = b^{\frac{2}{3} + \frac{2}{3}}

Factor integer

4 = 2^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

Refine

b^{\frac{2}{3} + \frac{2}{3}} = b^{\frac{4}{3}}

Multiply the numbers:

3 \cdot 2 = 6

\frac{1}{2} (16 x - x^{4})^{\frac{1}{2}}

e^{- 4 x} e^{4 x}

60795 e^{- 0.00020955 y}

12 \cdot 0.789 \cdot 1 0^{- 6}

(2 π) (1 0^{3}) (1.02 \cdot 1 0^{- 6})

What is (3a\sqrt[3]{2b^2})(2a^2\sqrt[3]{4b^2}) ?
The solution to (3a\sqrt[3]{2b^2})(2a^2\sqrt[3]{4b^2}) is 6\sqrt[3]{2}*2^{2/3}a^3b^{4/3}