What is 4*10^{-3}*(1/(0.2*10^{-3)})^2 ?

The solution to 4*10^{-3}*(1/(0.2*10^{-3)})^2 is 100000

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simplify 410^{-3}(1/(0.2*10^{-3)})^2

simplify

4 \cdot 1 0^{- 3} \cdot (\frac{1}{0.2 \cdot 1 0 ^{- 3}})^{2}

100000

Solution steps

4 \cdot 1 0^{- 3} (\frac{1}{0.2 \cdot 1 0 ^{- 3}})^{2}

1 0^{- 3} = \frac{1}{1000}

= 4 \cdot \frac{1}{1000} (\frac{1}{0.2 \cdot 1 0 ^{- 3}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{1}{0.2 \cdot 1 0 ^{- 3}})^{2} = \frac{1 ^{2}}{( 0.2 \cdot 1 0 ^{- 3} ) ^{2}}

= 4 \cdot \frac{1}{1000} \cdot \frac{1 ^{2}}{( 0.2 \cdot 1 0 ^{- 3} ) ^{2}}

1^{2} = 1

= 4 \cdot \frac{1}{1000} \cdot \frac{1}{( 0.2 \cdot 1 0 ^{- 3} ) ^{2}}

(0.2 \cdot 1 0^{- 3})^{2} = \frac{0.04}{1000000}

= 4 \cdot \frac{1}{1000} \cdot \frac{1}{\frac{0.04}{1000000}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= 4 \cdot \frac{1}{1000} \cdot \frac{1000000}{0.04}

Divide the numbers:

\frac{1000000}{0.04} = 25000000

= 4 \cdot \frac{1}{1000} \cdot 25000000

Multiply the numbers:

4 \cdot 25000000 = 100000000

= 100000000 \cdot \frac{1}{1000}

= \frac{1}{1000} \cdot 100000000

\frac{1}{1000} \cdot 100000000 = 100000

= 100000

\frac{x}{1 - x ^{2}}

(4 x + y) (3 x + 6 y)

e^{- \frac{x}{a}}

What is 4*10^{-3}*(1/(0.2*10^{-3)})^2 ?
The solution to 4*10^{-3}*(1/(0.2*10^{-3)})^2 is 100000