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Popular >

simplify e^{-ln|1+k(1-t)|}

Solution

simplify

e^{- l n ∣ 1 + k (1 - t) ∣}

Solution

\frac{1}{∣ k ( - t + 1 ) + 1 ∣}

Solution steps

e^{- l n ∣ 1 + k (1 - t) ∣}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n ∣ 1 + k (1 - t) ∣}}

e^{l n ∣ 1 + k (1 - t) ∣} = ∣ 1 + k (1 - t) ∣

= \frac{1}{∣ 1 + k ( - t + 1 ) ∣}

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Frequently Asked Questions (FAQ)

What is e^{-ln|1+k(1-t)|} ?
The solution to e^{-ln|1+k(1-t)|} is 1/(|k(-t+1)+1|)