What is the answer to (2(x-1))/3-(x+4}{15}+1=x-\frac{3(x-2))/5 ?

The answer to (2(x-1))/3-(x+4}{15}+1=x-\frac{3(x-2))/5 is x= 17/3

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(2(x-1))/3-(x+4}{15}+1=x-\frac{3(x-2))/5

\frac{2 ( x - 1 )}{3} - \frac{x + 4}{15} + 1 = x - \frac{3 ( x - 2 )}{5}

x = \frac{17}{3}

Decimal Notation

x = 5.66666 \dots

Solution steps

\frac{2 ( x - 1 )}{3} - \frac{x + 4}{15} + 1 = x - \frac{3 ( x - 2 )}{5}

Multiply by LCM

10 (x - 1) - (x + 4) + 15 = 15 x - 9 (x - 2)

Expand

- 9 (x - 2) : - 9 x + 18

9 x + 1 = 15 x - 9 x + 18

Add similar elements:

15 x - 9 x = 6 x

9 x + 1 = 6 x + 18

Expand

10 (x - 1) - (x + 4) + 15 : 9 x + 1

9 x + 1 = 6 x + 18

Move

1

to the right side

9 x = 6 x + 17

Move

6 x

to the left side

3 x = 17

Divide both sides by

3

x = \frac{17}{3}

\frac{2 a - 3}{6} = \frac{2 a}{3} + \frac{1}{2}

y^{3} - x^{3} y^{4}

- 19 = 5 (x + 9)

\frac{14 !}{9 ! 5 !}

What is the answer to (2(x-1))/3-(x+4}{15}+1=x-\frac{3(x-2))/5 ?
The answer to (2(x-1))/3-(x+4}{15}+1=x-\frac{3(x-2))/5 is x= 17/3
Solve for x: (2(x-1))/3-(x+4}{15}+1=x-\frac{3(x-2))/5
The solution is x= 17/3