What is e^{-2(t-t_{0})}u(t-2t_{0}) ?

The solution to e^{-2(t-t_{0})}u(t-2t_{0}) is (u(t-2t_{0}))/(e^{2(t-t_{0))}}

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simplify e^{-2(t-t_{0})}u(t-2t_{0})

simplify

e^{- 2 (t - t_{0})} u (t - 2 t_{0})

\frac{u ( t - 2 t _{0} )}{e ^{2 (t - t_{0})}}

Solution steps

e^{- 2 (t - t_{0})} u (t - 2 t_{0})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 (t - t_{0})}} u (t - 2 t_{0})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot u ( t - 2 t _{0} )}{e ^{2 (t - t_{0})}}

Multiply:

1 \cdot u = u

= \frac{u ( t - 2 t _{0} )}{e ^{2 (t - t_{0})}}

2.9 \cdot 1 0^{- 4} \cdot 58.3 3^{\frac{4}{3}}

(4 - x)^{- 1}

What is e^{-2(t-t_{0})}u(t-2t_{0}) ?
The solution to e^{-2(t-t_{0})}u(t-2t_{0}) is (u(t-2t_{0}))/(e^{2(t-t_{0))}}