What is 1/4 (k+1)^2(k+2)^2 ?

The solution to 1/4 (k+1)^2(k+2)^2 is ((k+1)^2(k+2)^2)/4

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simplify 1/4 (k+1)^2(k+2)^2

simplify

\frac{1}{4} (k + 1)^{2} (k + 2)^{2}

\frac{( k + 1 ) ^{2} ( k + 2 ) ^{2}}{4}

Solution steps

\frac{1}{4} (k + 1)^{2} (k + 2)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(k + 1)^{2} (k + 2)^{2} = ((k + 1) (k + 2))^{2}

= \frac{1}{4} ((k + 1) (k + 2))^{2}

((k + 1) (k + 2))^{2} = (k + 1)^{2} (k + 2)^{2}

= \frac{1}{4} (k + 1)^{2} (k + 2)^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( k + 1 ) ^{2} ( k + 2 ) ^{2}}{4}

Multiply:

1 \cdot (k + 1)^{2} = (k + 1)^{2}

= \frac{( k + 1 ) ^{2} ( k + 2 ) ^{2}}{4}

\frac{5 ^{8}}{8 !} e^{- 5}

x^{2} + 25^{a x}

5 e^{2 t} \cdot 5 e^{2 t}

(28 x^{5} y^{3} z^{2}) \cdot (4 x y z^{6})

\frac{e ^{9}}{e ^{4}}

What is 1/4 (k+1)^2(k+2)^2 ?
The solution to 1/4 (k+1)^2(k+2)^2 is ((k+1)^2(k+2)^2)/4