What are the solutions to the equation 13x^2-10x+13=0 ?

The solutions to the equation 13x^2-10x+13=0 are x= 5/13+i 12/13 ,x= 5/13-i 12/13

Find the zeros of 13x^2-10x+13=0

The zeros of 13x^2-10x+13=0 are x= 5/13+i 12/13 ,x= 5/13-i 12/13

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13 x^{2} - 10 x + 13 = 0

x = \frac{5}{13} + i \frac{12}{13}, x = \frac{5}{13} - i \frac{12}{13}

Solution steps

13 x^{2} - 10 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 13 \cdot 13}{2 \cdot 13}

Simplify

(- 10)^{2} - 4 \cdot 13 \cdot 13 : 24 i

x_{1, 2} = \frac{- ( - 10 ) \pm 24 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 24 i}{2 \cdot 13}, x_{2} = \frac{- ( - 10 ) - 24 i}{2 \cdot 13}

x = \frac{- ( - 10 ) + 24 i}{2 \cdot 13} : \frac{5}{13} + i \frac{12}{13}

x = \frac{- ( - 10 ) - 24 i}{2 \cdot 13} : \frac{5}{13} - i \frac{12}{13}

The solutions to the quadratic equation are:

x = \frac{5}{13} + i \frac{12}{13}, x = \frac{5}{13} - i \frac{12}{13}

0 - 5

7 g + 1.2 = 5 g - 2.4

\frac{2}{3 ^{3}}

(2 - i) (2 + i)

e^{- 100}

What are the solutions to the equation 13x^2-10x+13=0 ?
The solutions to the equation 13x^2-10x+13=0 are x= 5/13+i 12/13 ,x= 5/13-i 12/13
Find the zeros of 13x^2-10x+13=0
The zeros of 13x^2-10x+13=0 are x= 5/13+i 12/13 ,x= 5/13-i 12/13