What is (f\circ g)evaluar^2(x-4)(3x+2) ?

The solution to (f\circ g)evaluar^2(x-4)(3x+2) is e\circ lfgva^2ur^2(x-4)(3x+2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (f\circ g)evaluar^2(x-4)(3x+2)

simplify

(f \circ g) e v a l u a r^{2} (x - 4) (3 x + 2)

e \circ l f gv a^{2} u r^{2} (x - 4) (3 x + 2)

Solution steps

(f \circ g) e v a l u a r^{2} (x - 4) (3 x + 2)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

aa = a^{1 + 1}

= f \circ g e v l u a^{1 + 1} r^{2} (x - 4) (3 x + 2)

Add the numbers:

1 + 1 = 2

= f \circ g e v l u a^{2} r^{2} (x - 4) (3 x + 2)

3.98 \cdot 1 0^{- 4} \cdot 1.6358

(3.75 \cdot 1 0^{3}) (6 \cdot 1 0^{4})

(\frac{4}{5} x^{2} yz) \cdot (x^{3} y)

2^{3} \cdot e^{- 2}

(1 \cdot 1 0^{2} 0) \cdot (1.6 \cdot 1 0^{-} 19)

What is (f\circ g)evaluar^2(x-4)(3x+2) ?
The solution to (f\circ g)evaluar^2(x-4)(3x+2) is e\circ lfgva^2ur^2(x-4)(3x+2)