What is e^{-30t}(2cos(10t)+1sin(10t)) ?

The solution to e^{-30t}(2cos(10t)+1sin(10t)) is (2cos(10t)+sin(10t))/(e^{30t)}

Popular >

simplify e^{-30t}(2cos(10t)+1sin(10t))

simplify

e^{- 30 t} (2 cos (10 t) + 1 sin (10 t))

\frac{2 cos ( 10 t ) + sin ( 10 t )}{e ^{30 t}}

Solution steps

e^{- 30 t} (2 cos (10 t) + 1 \cdot sin (10 t))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{30 t}} (2 cos (10 t) + 1 \cdot sin (10 t))

Multiply:

1 \cdot sin (10 t) = sin (10 t)

= \frac{1}{e ^{30 t}} (2 cos (10 t) + sin (10 t))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 2 cos ( 10 t ) + sin ( 10 t ) )}{e ^{30 t}}

1 \cdot (2 cos (10 t) + sin (10 t)) = 2 cos (10 t) + sin (10 t)

= \frac{2 cos ( 10 t ) + sin ( 10 t )}{e ^{30 t}}

e^{k t} \cdot e^{- k t}

7.21 \cdot 1 0^{- 6}

5.44088 E 14 \cdot 6.63 \cdot 1 0^{- 34}

5 x^{2} (7 x^{3})

(9 \cdot 1 0^{9}) (\frac{( 8 \cdot 1 0 ^{- 6} ) ^{2}}{0.0 4 ^{2}})

What is e^{-30t}(2cos(10t)+1sin(10t)) ?
The solution to e^{-30t}(2cos(10t)+1sin(10t)) is (2cos(10t)+sin(10t))/(e^{30t)}