What is 2.302*10^{-22}*(0.101i+0.066j) ?

The solution to 2.302*10^{-22}*(0.101i+0.066j) is (2.302(0.101i+0.066j))/(10^{22)}

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simplify 2.30210^{-22}(0.101i+0.066j)

simplify

2.302 \cdot 1 0^{- 22} \cdot (0.101 i + 0.066 j)

\frac{2.302 ( 0.101 i + 0.066 j )}{1 0 ^{22}}

Solution steps

2.302 \cdot 1 0^{- 22} (0.101 i + 0.066 j)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 22} = \frac{1}{1 0 ^{22}}

= 2.302 \cdot \frac{1}{1 0 ^{22}} (0.101 i + 0.066 j)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2.302 \cdot 1 \cdot ( 0.101 i + 0.066 j )}{1 0 ^{22}}

Multiply the numbers:

2.302 \cdot 1 = 2.302

= \frac{2.302 ( 0.101 i + 0.066 j )}{1 0 ^{22}}

2.8 x 1 0^{- 3}

3 \frac{6 x}{x ^{2} - 9} d o mini o

e^{- 6.25}

e^{- 6.28}

7.3 \cdot 1 0^{- 7}

What is 2.302*10^{-22}*(0.101i+0.066j) ?
The solution to 2.302*10^{-22}*(0.101i+0.066j) is (2.302(0.101i+0.066j))/(10^{22)}