What is e^{-I*x}*(cos(x)+I*sin(x)) ?

The solution to e^{-I*x}*(cos(x)+I*sin(x)) is (cos(x)+Isin(x))/(e^{Ix)}

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simplify e^{-Ix}(cos(x)+I*sin(x))

simplify

e^{- I \cdot x} \cdot (cos (x) + I \cdot sin (x))

\frac{cos ( x ) + I sin ( x )}{e ^{I x}}

Solution steps

e^{- I x} (cos (x) + I sin (x))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{I x}} (cos (x) + I sin (x))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( cos ( x ) + I sin ( x ) )}{e ^{I x}}

1 \cdot (cos (x) + I sin (x)) = cos (x) + I sin (x)

= \frac{cos ( x ) + I sin ( x )}{e ^{I x}}

1 - cos (8 x) \cdot 1 + cos (8 x)

68 e^{- 0.0534 \cdot 4}

2 (e^{x})^{2}

8.44 \cdot 1 0^{- 4} \cdot 1.5

4 (e^{- (\frac{3}{4})^{2}})

What is e^{-I*x}*(cos(x)+I*sin(x)) ?
The solution to e^{-I*x}*(cos(x)+I*sin(x)) is (cos(x)+Isin(x))/(e^{Ix)}