What is e^{-2}(x^2+2y^2+4xy-2y-4x+1) ?

The solution to e^{-2}(x^2+2y^2+4xy-2y-4x+1) is 1/(e^2)(x^2+4xy-4x+2y^2+1-2y)

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simplify e^{-2}(x^2+2y^2+4xy-2y-4x+1)

simplify

e^{- 2} (x^{2} + 2 y^{2} + 4 x y - 2 y - 4 x + 1)

\frac{1}{e ^{2}} (x^{2} + 4 x y - 4 x + 2 y^{2} + 1 - 2 y)

Solution steps

e^{- 2} (x^{2} + 2 y^{2} + 4 x y - 2 y - 4 x + 1)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2}} (x^{2} + 4 x y - 4 x + 2 y^{2} + 1 - 2 y)

3.62 \cdot 1 0^{- 3}

(1.75 \cdot 1 0^{- 11}) (14 \cdot 1 0^{6}) (1.5 \cdot 1 0^{- 3})

e^{- 2 t} \cdot cos (4 t)

y e^{- 3 t}

(4 - x)^{- 1}

What is e^{-2}(x^2+2y^2+4xy-2y-4x+1) ?
The solution to e^{-2}(x^2+2y^2+4xy-2y-4x+1) is 1/(e^2)(x^2+4xy-4x+2y^2+1-2y)